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Are you sure you want to delete this answer? Age of the daughter—x: The man is 28, his daughter is Rate of the slower car—x: Maximum amount on food—x: Let daughter be x yrs old. Father is 18 years older than daughter.

In 10 years, father will be two times as old as daughter and subtract 2 years. How old is daughter now? Add 10 to get the ages in 10 yrs. In 10 years, father will be twice as old as daughter and less 2 yrs. But they must be consecutive, so you know that b is 1 greater than a and c is 2 greater than a. You only have so many options, i believe: Use algebra, like in question 1.

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